Which Are The Solutions Of X2 = –11X + 4?

Which Are The Solutions Of X2 = –11X + 4?. Step 1 :equation at the end of step 1 : Quadratic equations such as this one can be solved by completing the square.

Solve for x in the equation x2 +11x+121/4=125/4
Solve for x in the equation x2 +11x+121/4=125/4 from e-eduanswers.com

For this case we have the following polynomial: In order to complete the square, the equation must first be in the form x^ {2}+bx=c. X = −b+/−√b2−4ac 2a x = − b + / − b 2 − 4 a c 2 a.

For This Case We Have The Following Polynomial:

X = −b+/−√b2−4ac 2a x = − b + / − b 2 − 4 a c 2 a. X2 = −11x +4 x 2 = − 11 x + 4. Rewriting the polynomial we have:

The Equation Is Now Solved.

Add 24 24 to both sides of the equation. From here, we can solve the polynomial using the quadratic equation. Step 1 :equation at the end of step 1 :

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Step 1 :Trying To Factor By Splitting The Middle Term 1.1 Factoring X2+11X+18 The First Term Is, X2 Its.

X2 + 11x+24 = 0 x 2 + 11 x + 24 = 0. X2 +11x−4 =0 x 2 + 11 x − 4 = 0. Use the quadratic formula to find the solutions.

X = −11+/−√112−4(1)(−4) 2(1) X.

Quadratic equations such as this one can be solved by completing the square. Step 1 :equation at the end of step 1 : X2+11x+18=0 two solutions were found :

In Order To Complete The Square, The Equation Must First Be In The Form X^ {2}+Bx=C.

Substitute the values a = 1 a = 1, b = 11 b = 11, and c = 24 c = 24 into the quadratic formula and solve for x x.

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