What Are The Solutions To The Quadratic Equation (5Y + 6)2 = 24?. Step by step solution : Use the quadratic formula to find the solutions.
What are the solutions to the quadratic equation (5y + 6)2 = 24? Y = startfraction negative 6 + 2 startroot 6 endroot over 5 endfraction and y = startfraction negative 6 minus 2 startroot 6 endroot over 5 endfraction y = startfraction negative 6 + 2 startroot 6 endroot over 5 endfraction and y = startfraction 6 minus 2 startroot 6 endroot. The first term is, y2 its coefficient is 1.
25Y^2 + 60Y + 12 = 0.
(5y + 6)^2 = 24 25y^2 + 2 * 6 * 5y + 36 = 24 (5y + 6)^2 = 24. (5y + 6)2 = 24 ( 5 y + 6) 2 = 24.
The Area Of A Rectangular Room Is 750 Square Feet.
So y is equal to negative parentheses plus minus the square root parentheses, squared minus four times. Move 24 24 to the left side of the equation by subtracting it from both sides. X^2 = 9x + 6.
Use The Quadratic Formula To Find The Solutions.
The first term is, y2 its coefficient is 1. The middle term is, +5y its coefficient is 5. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation.
Which Is The Solution Set Of The Equation?
Multiply the coefficient of the first term by the constant 1 •. 3 🔴 on a question what are the solutions to the quadratic equation (5y + 6)2 = 24? Find all complex solutions (5y+6)^2=24.
Solve The Following Quadratic Equations By Factorization:
Which are the solutions of the quadratic equation? What was the resulting equation? What value of c makes x2 − 24x + c a perfect square trinomial?